5^(x+1)=2(^1-7x)

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Solution for 5^(x+1)=2(^1-7x) equation: 



5^(x+1)=2(^1-7x)

We move all terms to the left:

5^(x+1)-(2(^1-7x))=0



We calculate terms in parentheses: -(2(^1-7x)), so:

2(^1-7x)

We multiply parentheses

-14x+

We add all the numbers together, and all the variables

-14x

Back to the equation:

-(-14x)



We get rid of parentheses

5^(x+1)+14x=0

We add all the numbers together, and all the variables

14x+5^(x+1)=0

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